For CE transistor amplifier, the audio signal voltage across the collector resistance of 2 k Ω is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 kΩ, then the input signal voltage is

Question

For CE transistor amplifier, the audio signal voltage across the collector resistance of 2 k Ω is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 kΩ, then the input signal voltage is (A) 10 mV (B) 20 mV (C) 30 mV (D) 15 mV

Tardigrade Admin · Accepted Answer

β=100 RC=2 k Ω v 0=4 V R B =1 k Ω A =( v 0/ v i )=β ( R C / R B ) v i =( v 0 × R B /β R C )=(4 × 10/100 × 2 × 103)=20 mV

Q. For $CE$ transistor amplifier, the audio signal voltage across the collector resistance of $2 k Ω$ is $4 V$ . If the current amplification factor of the transistor is $100$ and the base resistance is $1 k Ω$ , then the input signal voltage is

10 mV

20 mV

30 mV

15 mV

$β = 100$
$R_{C} = 2 k Ω$
$v_{0} = 4 V$
$R_{B} = 1 k Ω$
$A = \frac{v _{0}}{v _{i}} = β \frac{R _{C}}{R _{B}}$
$v_{i} = \frac{v _{0} \times R _{B}}{β R _{C}} = \frac{4 \times 10}{100 \times 2 \times 1 0 ^{3}} = 20 mV$

Q. For CE transistor amplifier, the audio signal voltage across the collector resistance of 2kΩ is 4V. If the current amplification factor of the transistor is 100 and the base resistance is 1kΩ, then the input signal voltage is