For an ideal gas the fractional change in its volume per degree rise in temperature at constant pressure is equal to [T is absolute temperature of gas]

Question

For an ideal gas the fractional change in its volume per degree rise in temperature at constant pressure is equal to [T is absolute temperature of gas] (A) T° (B) T (C) T-1 (D) T2

Tardigrade Admin · Accepted Answer

P V=n R T ..... (1) P d v=n R d T ..... (2) Dividing (2) by (1) (d V/V)=(d T/T) Fractional change in volume per degree rise in temperature (d V/V)=(1/T)

Q. For an ideal gas the fractional change in its volume per degree rise in temperature at constant pressure is equal to $[T$ is absolute temperature of gas]

$T^{\circ}$

$T$

$T^{- 1}$

$T^{2}$

$P V = n RT$ ..... (1)
$P d v = n R d T$ ..... (2)
Dividing (2) by (1)
$\frac{d V}{V} = \frac{d T}{T}$
Fractional change in volume per degree rise in temperature
$\frac{d V}{V} = \frac{1}{T}$

Q. For an ideal gas the fractional change in its volume per degree rise in temperature at constant pressure is equal to [T is absolute temperature of gas]

T∘

T

T−1

T2

PV=nRT ..... (1) Pdv=nRdT ..... (2) Dividing (2) by (1) VdV​=TdT​ Fractional change in volume per degree rise in temperature VdV​=T1​

Q. For an ideal gas the fractional change in its volume per degree rise in temperature at constant pressure is equal to $[T$ is absolute temperature of gas]

$T^{\circ}$

$T$

$T^{- 1}$

$T^{2}$

$P V = n RT$ ..... (1)
$P d v = n R d T$ ..... (2)
Dividing (2) by (1)
$\frac{d V}{V} = \frac{d T}{T}$
Fractional change in volume per degree rise in temperature
$\frac{d V}{V} = \frac{1}{T}$