For an ideal gas graph is shown for three processes. Process 1, 2 and 3 are respectively. Work done (magnitude)

Question

For an ideal gas graph is shown for three processes. Process 1, 2 and 3 are respectively. Work done (magnitude) (A) Isobaric, adiabatic, isochoric (B) Adiabatic, isobaric, isochoric (C) Isochoric, adiabatic, isobaric (D) Isochoric, isobaric, adiabatic

Tardigrade Admin · Accepted Answer

Isochoric proceess d V=0 W=0 proceess 1 Isobaric: W=P Δ V=n R Δ T Adiabatic |W mid|=(n R Δ T/&gamma;-1) 0 <&gamma; -1 < 1 As work done in case of adiabatic process is more so process 3 is adiabatic and process 2 is isobaric.

Q. For an ideal gas graph is shown for three processes. Process 1, 2 and 3 are respectively. Work done (magnitude)

Isobaric, adiabatic, isochoric

Adiabatic, isobaric, isochoric

Isochoric, adiabatic, isobaric

Isochoric, isobaric, adiabatic

Isochoric proceess $d V = 0$
$W = 0$ proceess $1$
Isobaric : $W = P Δ V = n R Δ T$
Adiabatic $∣ ∣ W_{∣} ∣ ∣ = \frac{n R Δ T}{γ - 1} 0 < γ - 1 < 1$
As work done in case of adiabatic process is more so process 3 is adiabatic and process 2 is isobaric.

Q. For an ideal gas graph is shown for three processes. Process 1, 2 and 3 are respectively. Work done (magnitude)

Isobaric, adiabatic, isochoric

Adiabatic, isobaric, isochoric

Isochoric, adiabatic, isobaric

Isochoric, isobaric, adiabatic

Isochoric proceess dV=0 W=0 proceess 1 Isobaric : W=PΔV=nRΔT Adiabatic ∣∣​W∣​∣∣​=γ−1nRΔT​0<γ−1<1 As work done in case of adiabatic process is more so process 3 is adiabatic and process 2 is isobaric.

Isochoric proceess $d V = 0$
$W = 0$ proceess $1$
Isobaric : $W = P Δ V = n R Δ T$
Adiabatic $∣ ∣ W_{∣} ∣ ∣ = \frac{n R Δ T}{γ - 1} 0 < γ - 1 < 1$
As work done in case of adiabatic process is more so process 3 is adiabatic and process 2 is isobaric.