For a zero order reaction, K=1 × 10-3 mol L -1 s -1. If initial concentration of the reactant is 1.0 mol L -1, the concentration after 10 minutes would be

Question

For a zero order reaction, K=1 × 10-3 mol L -1 s -1. If initial concentration of the reactant is 1.0 mol L -1, the concentration after 10 minutes would be (A) 1 × 10-2 mol L -1 (B) 0.6 mol L -1 (C) 0.4 mol L -1 (D) 1.0 mol L -1

Tardigrade Admin · Accepted Answer

For zero order reaction, [ R ]0-[ R ] t = Kt 1-(R)t=1 × 10-3 × 60 × 10 (R)t ⇒ 1-0.6=0.4 mol L-1

Q. For a zero order reaction, $K = 1 \times 1 0^{- 3} m o l L^{- 1} s^{- 1}$ . If initial concentration of the reactant is $1.0 m o l L^{- 1}$ , the concentration after 10 minutes would be

$1 \times 1 0^{- 2} m o l L^{- 1}$

$0.6 m o l L^{- 1}$

$0.4 m o l L^{- 1}$

$1.0 m o l L^{- 1}$

For zero order reaction, $[R]_{0} - [R]_{t} = K t$
$1 - (R)_{t} = 1 \times 1 0^{- 3} \times 60 \times 10$
$(R)_{t} \Rightarrow 1 - 0.6 = 0.4 m o l L^{- 1}$

Q. For a zero order reaction, K=1×10−3molL−1s−1. If initial concentration of the reactant is 1.0molL−1, the concentration after 10 minutes would be

1×10−2molL−1

0.6molL−1

0.4molL−1

1.0molL−1