Question

For a zero order reaction, $K=1 \times 10^{-3} \,mol \,L ^{-1} s ^{-1}$. If initial concentration of the reactant is $1.0 \,mol \,L ^{-1}$, the concentration after 10 minutes would be

• A. $1 \times 10^{-2} \,mol \, L ^{-1}$
• B. $0.6 \,mol \,L ^{-1}$
• C. $0.4 \,mol \, L ^{-1}$
• D. $1.0 \,mol \, L ^{-1}$

Answer 1

Answer: (C)

For zero order reaction, $[ R ]_{0}-[ R ]_{ t }= Kt$
$1-(R)_{t}=1 \times 10^{-3} \times 60 \times 10$
$(R)_{t} \Rightarrow 1-0.6=0.4 \,mol \,L^{-1}$