For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 mA is

Question

For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 mA is (A) 6 mA (B) 4.8 mA (C) 24 mA (D) 8 mA

Tardigrade Admin · Accepted Answer

α=0.8 ⇒ β =(0.8/1-0.8)=4 Also β=(Δ ic/Δ ib) ⇒ Δ ic=β × Δ ib=4 × 6 =24 mA

Q. For a transistor, the current amplification factor is $0.8$ . The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by $6 m A$ is

6 mA

4.8 mA

24 mA

8 mA

$α = 0.8 \Rightarrow β$
$= \frac{0.8}{1 - 0.8} = 4$
Also $β = \frac{Δ i _{c}}{Δ i _{b}}$
$\Rightarrow Δ i_{c} = β \times Δ i_{b} = 4 \times 6$
$= 24 m A$

Q. For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6mA is