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Q. For a transistor, the current amplification factor is $0.8$. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by $6\, mA$ is

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$\alpha=0.8 \Rightarrow \beta$
$=\frac{0.8}{1-0.8}=4$
Also $\beta=\frac{\Delta i_{c}}{\Delta i_{b}}$
$\Rightarrow \Delta i_{c}=\beta \times \Delta i_{b}=4 \times 6$
$=24\, mA$