For a transistor in common base, the current gain is 0.95. If the load resistance is 400 kΩ and input resistance is 200 kΩ , then the voltage gain and power gain will be

Question

For a transistor in common base, the current gain is 0.95. If the load resistance is 400 kΩ and input resistance is 200 kΩ , then the voltage gain and power gain will be (A) 1900 and ,1800 (B) 1900 and 1805 (C) 5525 and 3591. (D) 1805 and 1900

Tardigrade Admin · Accepted Answer

Given, α =0.95, R0=400× 103 Ω Ri=200 Ω As, voltage gain =α (R0/Ri) =0.95× (400× 103/200) =1900 Power gain = Voltage gain × Current gain =1900× 0.95 =1805

Q. For a transistor in common base, the current gain is 0.95. If the load resistance is $400 k Ω$ and input resistance is $200 k Ω,$ then the voltage gain and power gain will be

1900 and ,1800

1900 and 1805

5525 and 3591.

1805 and 1900

Given, $α = 0.95, R_{0} = 400 \times 10^{3} Ω$
$R_{i} = 200 Ω$
As, voltage gain $= α \frac{R _{0}}{R _{i}}$
$= 0.95 \times \frac{400 \times 10 ^{3}}{200}$
$= 1900$
Power gain = Voltage gain $\times$ Current gain
$= 1900 \times 0.95$ $= 1805$

Q. For a transistor in common base, the current gain is 0.95. If the load resistance is 400kΩ and input resistance is 200kΩ, then the voltage gain and power gain will be