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Q. For a transistor in common base, the current gain is 0.95. If the load resistance is $ 400\,k\Omega $ and input resistance is $ 200\,k\Omega , $ then the voltage gain and power gain will be

Jharkhand CECEJharkhand CECE 2013

Solution:

Given, $ \alpha =0.95,\,{{R}_{0}}=400\times {{10}^{3}}\,\Omega $
$ {{R}_{i}}=200\,\Omega $
As, voltage gain $ =\alpha \frac{{{R}_{0}}}{{{R}_{i}}} $
$ =0.95\times \frac{400\times {{10}^{3}}}{200} $
$ =1900 $
Power gain = Voltage gain $ \times $ Current gain
$ =1900\times 0.95 $ $ =1805 $