For a solenoid having a primary coil of N1 turns and a secondary coil of N2 turns, the coefficient of mutual inductance is :

Question

For a solenoid having a primary coil of N1 turns and a secondary coil of N2 turns, the coefficient of mutual inductance is : (A) μ0μr (N1N2/l) (B)  (μ 0μ rN1N2/Al)  (C)  μ 0μ rN1N2Al  (D)  (μ 0μ 1N1N2A/l)

Tardigrade Admin · Accepted Answer

Coefficient of mutual inductance M=(φ/Ip) =(μ0 μr N1 N2 A IP/I IP) =(μ0 μr N1 N2 A) / l where A and l are the length and area of cross-section respectively

Q. For a solenoid having a primary coil of $N_{1}$ turns and a secondary coil of $N_{2}$ turns, the coefficient of mutual inductance is :

$μ_{0} μ_{r} \frac{N _{1} N _{2}}{l}$

$\frac{μ _{0} μ _{r} N _{1} N _{2}}{A l}$

$μ_{0} μ_{r} N_{1} N_{2} A l$

$\frac{μ _{0} μ _{1} N _{1} N _{2} A}{l}$

Coefficient of mutual inductance $M = \frac{ϕ}{I _{p}}$
$= \frac{μ _{0} μ _{r} N _{1} N _{2} A I _{P}}{I I _{P}}$
$= (μ_{0} μ_{r} N_{1} N_{2} A) / l$
where $A$ and $l$ are the length and area of cross-section respectively

Q. For a solenoid having a primary coil of N1​ turns and a secondary coil of N2​ turns, the coefficient of mutual inductance is :

μ0​μr​lN1​N2​​

Alμ0​μr​N1​N2​​

μ0​μr​N1​N2​Al

lμ0​μ1​N1​N2​A​