Tardigrade
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Tardigrade
Question
Chemistry
For a shell of principal quantum number n = 4, there are
Q. For a shell of principal quantum number n = 4, there are
1852
187
Structure of Atom
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A
16 orbitals
49%
B
8 subshells
9%
C
18 electrons (maximum)
16%
D
4 electrons with l = 3.
26%
Solution:
Maximum number of orbitals=
n
2
=
16
Maximum number of electrons =
2
n
2
=
32
Number of subshells when n = 4
i.e., n = 1, 2, 3, 4 (K, L, M, N)