Tardigrade
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Tardigrade
Question
Physics
For a reversible process, necessary condition is
Q. For a reversible process, necessary condition is
2769
210
Thermodynamics
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A
that, in the whole cycle of the system, the loss of any type of heat energy should be zero
28%
B
that the process should be too fast
14%
C
that the process should be slow so that the working substance should remain in thermal and mechanical equilibrium with the surroundings.
36%
D
that the loss of energy should be zero and it should be quasistatic
22%
Solution:
Quasistatic takes care of the thermal, mechanical and chemical equilibrium (thermodynamic equilibria). No dissipative forces like friction, viscosity or electrical resistance etc. must be there which create a loss of energy.