For a reaction, X(g)→ Y(g)+Z(g) the half-life period is 10 min. In What period of time would the concentration of X be reduced to 10 % of original concentration

Question

For a reaction, X(g)→ Y(g)+Z(g) the half-life period is 10 min. In What period of time would the concentration of X be reduced to 10 % of original concentration (A) 20 min (B) 33 min (C) 15 min (D) 25 min

Tardigrade Admin · Accepted Answer

X(g)→ Y(g)+Z(g) The reaction is a first-order reaction hence, K=(0.693/t12)=(2.303/t) log(a/a-x) =(0.693/10 min) =(2.303/t)log (a/a10)=(0.693/10)=(2.303/t) log 10 ∴ t=(2.303×10/693)=33 min

Q. For a reaction, X(g)→Y(g)+Z(g)the half-life period is 10 min. In What period of time would the concentration of X be reduced to 10% of original concentration

20 min

33 min

15 min

25 min

X(g)​→Y(g)​+Z(g)​ The reaction is a first-order reaction hence, K=t12​0.693​=t2.303​loga−xa​ =10min0.693​ =t2.303​loga10a​=100.693​=t2.303​ log 10 ∴t=6932.303×10​=33min

Q. For a reaction, $X (g) \to Y (g) + Z (g)$ the half-life period is $10$ min. In What period of time would the concentration of $X$ be reduced to $10%$ of original concentration