For a reaction scheme A -[k1] B -[k2] C , if the rate of formation of B is set to be zero then the concentration of B is given by :

Question

For a reaction scheme A ->[k1] B ->[k2] C , if the rate of formation of B is set to be zero then the concentration of B is given by : (A) ((k1/k2))[A] (B) k1k2[A] (C) (k1+k2) [A] (D) ((k1/k2))[ B ]

Tardigrade Admin · Accepted Answer

Solution:- (A) (( k 1/ k 2))[ A ] A stackrel k 1 longrightarrow B stackrel k 2 longrightarrow C According to given question, ( d [ B ]/ dt )=0= K 1[ A ]- K 2[ B ] ⇒[ B ]=( K 1/ K 2)[ A ]

Q. For a reaction scheme $A k X_{1} B k X_{2} C$ , if the rate of formation of $B$ is set to be zero then the concentration of $B$ is given by :

$(\frac{k _{1}}{k _{2}}) [A]$

$k_{1} k_{2} [A]$

$(k_{1} + k_{2}) [A]$

$(\frac{k _{1}}{k _{2}}) [B]$

Solution:- (A) $(\frac{k _{1}}{k _{2}}) [A]$
$A ⟶ k_{1} B ⟶ k_{2} C$
According to given question,
$\frac{d [ B ]}{d t} = 0 = K_{1} [A] - K_{2} [B]$
$\Rightarrow [B] = \frac{K _{1}}{K _{2}} [A]$

Q. For a reaction scheme AkX1​​BkX2​​C , if the rate of formation of B is set to be zero then the concentration of B is given by :

(k2​k1​​)[A]

k1​k2​[A]

(k1​+k2​)[A]

(k2​k1​​)[B]