Tardigrade
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Tardigrade
Question
Chemistry
For a reaction Ea = 0 and k - 3.2 × 104 s-1 at 300 K. The value of k at 310 K would be :
Q. For a reaction
E
a
=
0
and
k
−
3.2
×
1
0
4
s
−
1
at
300
K
.
The value of
k
at
310
K
would be :
3035
204
Chemical Kinetics
Report Error
A
6.4
×
1
0
4
s
−
1
33%
B
3.2
×
1
0
4
s
−
1
59%
C
3.2
×
1
0
8
s
−
1
7%
D
3.2
×
1
0
5
s
−
1
0%
Solution:
k
=
A
e
−
E
a
/
RT
When
E
a
=
0
,
k
=
A
=
constant
∴
k
310
=
k
300
=
3.2
×
1
0
4
s
−
1