For a reaction textA arrow textB, textE texta = 10 text kJ/mol, textΔH = 5 textkJ/mol text. Thus potential energy profile for this reaction is

Question

For a reaction textA arrow textB, textE texta = 10 text kJ/mol, textΔH = 5 textkJ/mol text. Thus potential energy profile for this reaction is (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

Δ H =( E a ) f -( E a ) b 5=10-( E a ) b ( E a ) b =5 kJ / mol ( E a ) f >( E a ) b hence option ( B ) is correct

Q. For a reaction $A \to B, E_{a} = 10 kJ/mol, ΔH = 5 kJ/mol .$ Thus potential energy profile for this reaction is

$Δ H = (E_{a})_{f} - (E_{a})_{b}$

$5 = 10 - (E_{a})_{b}$

$(E_{a})_{b} = 5 k J / m o l$

$(E_{a})_{f} > (E_{a})_{b}$ hence option $(B)$ is correct

Q. For a reaction A→B,Ea​=10 kJ/mol,ΔH=5kJ/mol. Thus potential energy profile for this reaction is

ΔH=(Ea​)f​−(Ea​)b​ 5=10−(Ea​)b​ (Ea​)b​=5kJ/mol (Ea​)f​>(Ea​)b​ hence option (B) is correct

Q. For a reaction $A \to B, E_{a} = 10 kJ/mol, ΔH = 5 kJ/mol .$ Thus potential energy profile for this reaction is

$Δ H = (E_{a})_{f} - (E_{a})_{b}$

$5 = 10 - (E_{a})_{b}$

$(E_{a})_{b} = 5 k J / m o l$

$(E_{a})_{f} > (E_{a})_{b}$ hence option $(B)$ is correct