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Tardigrade
Question
Chemistry
For a reaction A → B; Δ H = 20 kJ mol-1 the activation energy of the forward reaction is 85 kJ/mol. The activation energy of the backward reaction will be
Q. For a reaction
A
→
B
;
Δ
H
=
20
k
J
m
o
l
−
1
the activation energy of the forward reaction is
85
k
J
/
m
o
l
. The activation energy of the backward reaction will be
2152
192
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A
105 kJ/mol
28%
B
65 kJ/mol
50%
C
45 kJ/mol
11%
D
75 kJ/mol
11%
Solution:
Energy of activation for forward reaction
(
E
a
)
=
85
k
J
/
m
o
l
and
Δ
H
=
20
k
J
/
m
o
l
∴
Energy of activation for backward reaction
E
b
=
E
a
−
Δ
H
=
85
−
20
=
65
k
J
m
o
l
−
1