For a pseudo first order reaction, CH3COOC2H5+H2O xrightleftharpoonsH+ CH3COOH+C2H5OH the net rate is given by (d x/d t)=4×10-4 L mol-1 s-1 [(CH3COOC2H5)]-3×104L mol-1 s-1[CH3COOH][C2H5OH] Then, the equilibrium constant of the reaction would be

Question

For a pseudo first order reaction, CH3COOC2H5+H2O xrightleftharpoonsH+ CH3COOH+C2H5OH the net rate is given by (d x/d t)=4×10-4 L mol-1 s-1 [(CH3COOC2H5)]-3×104L mol-1 s-1[CH3COOH][C2H5OH] Then, the equilibrium constant of the reaction would be (A) 1.3×10-7 mol L-1 s-1 (B) 1.3×10-6 mol L-1 s-1 (C) 1.33×10-9 mol L-1 (D) 1.33×10-8 mol L-1

Tardigrade Admin · Accepted Answer

Correct answer is (d) 1.33×10-8 mol L-1

$1.3 \times 1 0^{- 7} m o l L^{- 1} s^{- 1}$

$1.3 \times 1 0^{- 6} m o l L^{- 1} s^{- 1}$

$1.33 \times 1 0^{- 9} m o l L^{- 1}$

$1.33 \times 1 0^{- 8} m o l L^{- 1}$

Correct answer is (d) $1.33 \times 1 0^{- 8} m o l L^{- 1}$

Q. For a pseudo first order reaction, CH3​COOC2​H5​+H2​OH+​CH3​COOH+C2​H5​OH the net rate is given by dtdx​=4×10−4Lmol−1s−1[(CH3​COOC2​H5​)]−3×104Lmol−1s−1[CH3​COOH][C2​H5​OH] Then, the equilibrium constant of the reaction would be

1.3×10−7molL−1s−1

1.3×10−6molL−1s−1

1.33×10−9molL−1

1.33×10−8molL−1

Correct answer is (d) 1.33×10−8molL−1

$1.3 \times 1 0^{- 7} m o l L^{- 1} s^{- 1}$

$1.3 \times 1 0^{- 6} m o l L^{- 1} s^{- 1}$

$1.33 \times 1 0^{- 9} m o l L^{- 1}$

$1.33 \times 1 0^{- 8} m o l L^{- 1}$

Correct answer is (d) $1.33 \times 1 0^{- 8} m o l L^{- 1}$