For a perfect gas, two pressures P 1 and P 2 are shown in figure. The graph shows:

Question

For a perfect gas, two pressures P 1 and P 2 are shown in figure. The graph shows: (A) P 1 > P 2 (B) P 1< P 2 (C) P 1= P 2 (D) Insufficient data to draw any conclusion

Tardigrade Admin · Accepted Answer

PV = nRT ( V / T )=( nR / P ) ( nR / P 1)<( nR / P 2) P 2< P 1

Q. For a perfect gas, two pressures $P_{1}$ and $P_{2}$ are shown in figure. The graph shows:

$P_{1} > P_{2}$

$P_{1} < P_{2}$

$P_{1} = P_{2}$

Insufficient data to draw any conclusion

$P V = n RT$
$\frac{V}{T} = \frac{n R}{P}$
$\frac{n R}{P _{1}} < \frac{n R}{P _{2}}$
$P_{2} < P_{1}$

Q. For a perfect gas, two pressures P1​ and P2​ are shown in figure. The graph shows:

P1​>P2​

P1​<P2​

P1​=P2​