Question

For a perfect gas, two pressures $P _{1}$ and $P _{2}$ are shown in figure. The graph shows:

• A. $P _{1} > P _{2}$
• B. $P _{1}< P _{2}$
• C. $P _{1}= P _{2}$
• D. Insufficient data to draw any conclusion

Answer 1

Answer: (A)

$PV = nRT$
$\frac{ V }{ T }=\frac{ nR }{ P }$
$\frac{ nR }{ P _{1}}<\frac{ nR }{ P _{2}}$
$P _{2}< P _{1}$