For a particle undergoing rectilinear motion with uniform acceleration, the magnitude of displacement is one third the distance covered in some time interval. The magnitude of final velocity is less than magnitude of initial velocity for this time interval. Then the ratio of initial speed velocity to the final speed for this time interval is:

Question

For a particle undergoing rectilinear motion with uniform acceleration, the magnitude of displacement is one third the distance covered in some time interval. The magnitude of final velocity is less than magnitude of initial velocity for this time interval. Then the ratio of initial speed velocity to the final speed for this time interval is: (A) √2 (B) 2 (C) √3 (D) 3

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/bd5d4c53ad856a5518e0c6abc6f6737b-.png" /> Let u and v denote initial and final velocities. The nature of motion is indicated in diagram Hence initial and final speeds are given by equation 02 = u2- 2a × 2s and v2 = 02 +2 as ∴ v =(u/√2) or (u/v) = √2

$2$

2

$3$

3

Let $u$ and $v$ denote initial and final velocities. The nature of motion is indicated in diagram

Hence initial and final speeds are given by equation

$0^{2} = u^{2} - 2 a \times 2 s$ and $v^{2} = 0^{2} + 2 a s$

$∴ v = \frac{u}{2}$ or $\frac{u}{v} = 2$

2​

2

3​

3

Let u and v denote initial and final velocities. The nature of motion is indicated in diagram Hence initial and final speeds are given by equation 02=u2−2a×2s and v2=02+2as ∴v=2​u​ or vu​=2​

$2$

$3$

Let $u$ and $v$ denote initial and final velocities. The nature of motion is indicated in diagram

Hence initial and final speeds are given by equation

$0^{2} = u^{2} - 2 a \times 2 s$ and $v^{2} = 0^{2} + 2 a s$

$∴ v = \frac{u}{2}$ or $\frac{u}{v} = 2$