For a moving coil galvanometer, the deflection in the coil is 0.05 rad when a current of 10 mA is field is 0,01 T and the number of turns in the coil is 200 , the area of each tum (in cm 2 ) is :

Question

For a moving coil galvanometer, the deflection in the coil is 0.05 rad when a current of 10 mA is field is 0,01 T and the number of turns in the coil is 200 , the area of each tum (in cm 2 ) is : (A) 2.0 (B) 1.0 (C) 1.5 (D) 0.5

Tardigrade Admin · Accepted Answer

τ= K θ NiAB = K θ A =( K θ/ NiB )=(4 × 10-5 × 0.05/200 × 10 × 10-3 × 0.01) On solving A =10-4 m 2=1 cm 2

Q. For a moving coil galvanometer, the deflection in the coil is $0.05$ rad when a current of $10 m A$ is field is $0, 01 T$ and the number of turns in the coil is $200$ , the area of each tum (in $c m^{2}$ ) is :

$2.0$

$1.0$

$1.5$

$0.5$

$τ = K θ$
$N i A B = K θ$
$A = \frac{K θ}{N i B} = \frac{4 \times 1 0 ^{- 5} \times 0.05}{200 \times 10 \times 1 0 ^{- 3} \times 0.01}$
On solving $A = 1 0^{- 4} m^{2} = 1 c m^{2}$

Q. For a moving coil galvanometer, the deflection in the coil is 0.05 rad when a current of 10mA is field is 0,01T and the number of turns in the coil is 200 , the area of each tum (in cm2 ) is :

2.0

1.0

1.5

0.5