For a liquid the vapour pressure is given by log10 P=(- 400/T)+10 Vapour pressure of the liquid is 10x mm Hg at 400 K . The value of x will be?

Question

For a liquid the vapour pressure is given by log10 P=(- 400/T)+10 Vapour pressure of the liquid is 10x mm Hg at 400 K . The value of x will be? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

log10 P=-(400/T)+10=-(400/400)+10=9 P=109 mm Hg x = 9 .

Q. For a liquid the vapour pressure is given by
$lo g_{10} P = \frac{- 400}{T} + 10$
Vapour pressure of the liquid is $1 0^{x} mm H g$ at $400 K$ . The value of $x$ will be?

$lo g_{10} P = - \frac{400}{T} + 10 = - \frac{400}{400} + 10 = 9$
$P = 1 0^{9} mm H g$
$x = 9$ .

Q. For a liquid the vapour pressure is given by log10​P=T−400​+10 Vapour pressure of the liquid is 10xmmHg at 400K . The value of x will be?

log10​P=−T400​+10=−400400​+10=9 P=109mmHg x=9 .

Q. For a liquid the vapour pressure is given by
$lo g_{10} P = \frac{- 400}{T} + 10$
Vapour pressure of the liquid is $1 0^{x} mm H g$ at $400 K$ . The value of $x$ will be?

$lo g_{10} P = - \frac{400}{T} + 10 = - \frac{400}{400} + 10 = 9$
$P = 1 0^{9} mm H g$
$x = 9$ .