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Q. For a liquid the vapour pressure is given by
$\log_{10} P=\frac{- 400}{T}+10$
Vapour pressure of the liquid is $10^{x} \, mm \, Hg$ at $400\,K$ . The value of $x$ will be?

NTA AbhyasNTA Abhyas 2022

Solution:

$\log_{10} P=-\frac{400}{T}+10=-\frac{400}{400}+10=9$
$P=10^{9} \, mm \, Hg$
$x = 9$ .