For a linear plot of log(x/m) versus log p in a Freundlich absorption isotherm, which of the following statements is correct? (k and n are constants)

Question

For a linear plot of log(x/m) versus log p in a Freundlich absorption isotherm, which of the following statements is correct? (k and n are constants) (A) log (1/n) appears as the intercept (B) Both k and 1/n appear in the slope term (C) 1/n appears as the intercept (D) Only 1/n appears as the slope

Tardigrade Admin · Accepted Answer

According to Freundlich isotherm <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-y0lc3l8mk7dlyolj.jpg" /> (x/m)=k.p1 / n log(x/m)=logk+(1/n)logP So intercept is log k and slope is (1/n)

Q. For a linear plot of log(x/m) versus log p in a Freundlich absorption isotherm, which of the following statements is correct? (k and n are constants)

log (1/n) appears as the intercept

Both k and 1/n appear in the slope term

1/n appears as the intercept

Only 1/n appears as the slope

According to Freundlich isotherm

$\frac{x}{m} = k . p^{1/ n}$
$l o g \frac{x}{m} = l o g k + \frac{1}{n} l o g P$
So intercept is log k and slope is $\frac{1}{n}$

Q. For a linear plot of log(x/m) versus log p in a Freundlich absorption isotherm, which of the following statements is correct? (k and n are constants)

log (1/n) appears as the intercept

Both k and 1/n appear in the slope term

1/n appears as the intercept

Only 1/n appears as the slope

According to Freundlich isotherm mx​=k.p1/n logmx​=logk+n1​logP So intercept is log k and slope is n1​

According to Freundlich isotherm

$\frac{x}{m} = k . p^{1/ n}$
$l o g \frac{x}{m} = l o g k + \frac{1}{n} l o g P$
So intercept is log k and slope is $\frac{1}{n}$