For a gaseous reaction, following data is given: A arrow B, k1=1015 e- 2000 / T C arrow D, k2=1014 e- 1000 / T The temperature at which k1=k2 is :

Question

For a gaseous reaction, following data is given: A arrow B, k1=1015 e- 2000 / T C arrow D, k2=1014 e- 1000 / T The temperature at which k1=k2 is : (A) 1000 K (B) 2000 K (C) 868.82 K (D) 434.2 K

Tardigrade Admin · Accepted Answer

When k1=k2 , 1015 e- 2000 / T=1014 e- 1000 / T 10=e1000 / T 2.303 log 10=(1000/T) T=434.2 K

Q. For a gaseous reaction, following data is given:
$A \to B, k_{1} = 1 0^{15} e^{- 2000/ T}$
$C \to D, k_{2} = 1 0^{14} e^{- 1000/ T}$
The temperature at which $k_{1} = k_{2}$ is :

$1000 K$

$2000 K$

$868.82 K$

$434.2 K$

When $k_{1} = k_{2}$ ,
$1 0^{15} e^{- 2000/ T} = 1 0^{14} e^{- 1000/ T}$
$10 = e^{1000/ T}$
$2.303 l o g 10 = \frac{1000}{T}$
$T = 434.2 K$

Q. For a gaseous reaction, following data is given: A→B,k1​=1015e−2000/T C→D,k2​=1014e−1000/T The temperature at which k1​=k2​ is :

1000K

2000K

868.82K

434.2K