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Tardigrade
Question
Chemistry
For a gaseous reaction, following data is given: A arrow B, k1=1015 e- 2000 / T C arrow D, k2=1014 e- 1000 / T The temperature at which k1=k2 is :
Q. For a gaseous reaction, following data is given:
A
→
B
,
k
1
=
1
0
15
e
−
2000/
T
C
→
D
,
k
2
=
1
0
14
e
−
1000/
T
The temperature at which
k
1
=
k
2
is :
1321
184
NTA Abhyas
NTA Abhyas 2022
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A
1000
K
B
2000
K
C
868.82
K
D
434.2
K
Solution:
When
k
1
=
k
2
,
1
0
15
e
−
2000/
T
=
1
0
14
e
−
1000/
T
10
=
e
1000/
T
2.303
l
o
g
10
=
T
1000
T
=
434.2
K