Tardigrade
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Tardigrade
Question
Chemistry
For a gaseous reaction, following data is given: A→ B, k1= 1015e-2000/T C → D, k2 = 1014e-1000/T The temperature at which k1=k2 is:
Q. For a gaseous reaction, following data is given:
A
→
B
,
k
1
=
1
0
15
e
−
2000/
T
C
→
D
,
k
2
=
1
0
14
e
−
1000/
T
The temperature at which
k
1
=
k
2
is:
2557
168
Chemical Kinetics
Report Error
A
1000
K
100%
B
2000
K
0%
C
868.82
K
0%
D
434.2
K
0%
Solution:
k
1
=
k
2
1
0
15
e
−
2000/
T
=
1
0
14
e
−
1000/
T
10
=
e
1000/
T
2.303
l
o
g
10
=
T
1000
T
=
434.2
K