For a gaseous reaction 2 A + B leftharpoons C + D, the partial pressures of A , B , C and D at equilibrium are 0.5, 0.8,0.7 and 1.2 atm. The value of K p for this reaction is

Question

For a gaseous reaction 2 A + B leftharpoons C + D, the partial pressures of A , B , C and D at equilibrium are 0.5, 0.8,0.7 and 1.2 atm. The value of K p for this reaction is (A) 2.4 atm (B) 6.2 atm -2 (C) 4.2 atm -1 (D) 8.4 atm -3

Tardigrade Admin · Accepted Answer

The equilibrium constant for the reaction in terms of partial pressure K p =(( P e ) ×( P D )/( P A )2 ×( P B )) =(0.7 × 1.2/(0.5)2 × 0.8) =4.2 atm -1

Q. For a gaseous reaction $2 A + B ⇌ C + D$ , the partial pressures of $A, B, C$ and $D$ at equilibrium are $0.5$ , $0.8, 0.7$ and $1.2 a t m$ . The value of $K_{p}$ for this reaction is

$2.4 a t m$

$6.2 a t m^{- 2}$

$4.2 a t m^{- 1}$

$8.4 a t m^{- 3}$

The equilibrium constant for the reaction in terms of partial pressure
$K_{p} = \frac{( P _{e} ) \times ( P _{D} )}{( P _{A} ) ^{2} \times ( P _{B} )}$
$= \frac{0.7 \times 1.2}{( 0.5 ) ^{2} \times 0.8}$
$= 4.2 a t m^{- 1}$

Q. For a gaseous reaction 2A+B⇌C+D, the partial pressures of A,B,C and D at equilibrium are 0.5, 0.8,0.7 and 1.2atm. The value of Kp​ for this reaction is

2.4atm

6.2atm−2

4.2atm−1

8.4atm−3