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Q. For a gaseous reaction $2 A + B \rightleftharpoons C + D$, the partial pressures of $A , B , C$ and $D$ at equilibrium are $0.5$, $0.8,0.7$ and $1.2 \,atm$. The value of $K _{ p }$ for this reaction is

Equilibrium

Solution:

The equilibrium constant for the reaction in terms of partial pressure
$K _{ p }=\frac{\left( P _{ e }\right) \times\left( P _{ D }\right)}{\left( P _{ A }\right)^{2} \times\left( P _{ B }\right)}$
$=\frac{0.7 \times 1.2}{(0.5)^{2} \times 0.8}$
$=4.2 \,atm ^{-1}$