For a first order reaction, n A longrightarrow B whose concentration vs time curve is as shown in the figure. If half life for the reaction is 24 minutes. Find out the value of n.

Question

For a first order reaction, n A longrightarrow B whose concentration vs time curve is as shown in the figure. If half life for the reaction is 24 minutes. Find out the value of n. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/f99f8a855f6938b6a1ec3c2bf8d457d9-.png" /> and At 48 min a-n x=x ∴ ( ln 2/24)=(1/48) ln (a/(a / n+1)) 4=n+1 n=3

Q. For a first order reaction, $n A ⟶ B$ whose concentration vs time curve is as shown in the figure. If half life for the reaction is $24$ minutes. Find out the value of $n$ .

and At $48 min a - n x = x$
$∴ \frac{l n 2}{24} = \frac{1}{48} ln \frac{a}{( a / n + 1 )}$
$4 = n + 1$
$n = 3$

Q. For a first order reaction, nA⟶B whose concentration vs time curve is as shown in the figure. If half life for the reaction is 24 minutes. Find out the value of n.

and At 48mina−nx=x ∴24ln2​=481​ln(a/n+1)a​ 4=n+1 n=3

Q. For a first order reaction, $n A ⟶ B$ whose concentration vs time curve is as shown in the figure. If half life for the reaction is $24$ minutes. Find out the value of $n$ .

and At $48 min a - n x = x$
$∴ \frac{l n 2}{24} = \frac{1}{48} ln \frac{a}{( a / n + 1 )}$
$4 = n + 1$
$n = 3$