For a dipole q=2× 10- 6C;d=0.01m; find the maximum torque on the dipole if E=5× 105NC- 1 :-

Question

For a dipole q=2× 10- 6C;d=0.01m; find the maximum torque on the dipole if E=5× 105NC- 1 :- (A) 1× 10- 3Nm- 1 (B) 10× 10- 3Nm- 1 (C) 10× 10- 3Nm (D) 1× 10- 4Nm

Tardigrade Admin · Accepted Answer

overset arrow τ= overset arrow P × overset arrow E , ( overset arrow P) = q d τmax=P⋅ E=qdE τmax=2× 10- 6× 0.01× 5× 105 =10× 10- 3Nm

Q. For a dipole $q = 2 \times 1 0^{- 6} C; d = 0.01 m;$ find the maximum torque on the dipole if $E = 5 \times 1 0^{5} N C^{- 1}$ :-

$1 \times 1 0^{- 3} N m^{- 1}$

$10 \times 1 0^{- 3} N m^{- 1}$

$10 \times 1 0^{- 3} N m$

$1 \times 1 0^{- 4} N m$

$τ \to = P \to \times E \to, (P \to) = q d$
$τ_{ma x} = P \cdot E = q d E$
$τ_{ma x} = 2 \times 1 0^{- 6} \times 0.01 \times 5 \times 1 0^{5}$
$= 10 \times 1 0^{- 3} N m$

Q. For a dipole q=2×10−6C;d=0.01m; find the maximum torque on the dipole if E=5×105NC−1 :-

1×10−3Nm−1

10×10−3Nm−1

10×10−3Nm

1×10−4Nm