When V is negative, diode is in reverse bias and it does not conducts.
So, current-voltage relationship followed from Ohm’s law is, V=IR ∴V−I graph is straight line.
As V grows in positive region, diode becomes conductive after knee voltage and after that current is approximately, I=IseV/nVT
where, Is= saturation current in reverse bias, V= voltage across diode n and VT are diode constants. So, correct graph