For a dimerization reaction, 2 A ( g ) arrow A 2( g ) at 298 K , Δ U ominus,=-20 kJ mol -1, Δ S ominus=-30 J K -1 mol -1, then the Δ G ominus will beJ.

Question

For a dimerization reaction, 2 A ( g ) arrow A 2( g ) at 298 K , Δ U ominus,=-20 kJ mol -1, Δ S ominus=-30 J K -1 mol -1, then the Δ G ominus will beJ. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ G °=Δ H °- T Δ S ° =(Δ U °+Δ n g RT )- T Δ S ° .=[ -20+(-1)) (8.314/1000) × 298 -(298/1000) ×(-30)] kJ =-13.537572 kJ =-13537.57 Joule

Q. For a dimerization reaction,
$2 A (g) \to A_{2} (g)$
at $298 K, Δ U^{⊖}, = - 20 k J m o l^{- 1}, Δ S^{⊖} = - 30 J$
$K^{- 1} m o l^{- 1}$ , then the $Δ G^{⊖}$ will be______J.

$Δ G^{\circ} = Δ H^{\circ} - T Δ S^{\circ}$

$= (Δ U^{\circ} + Δ n_{g} RT) - T Δ S^{\circ}$

$= [{- 20 + (- 1)) \frac{8.314}{1000} \times 298} - \frac{298}{1000} \times (- 30)] k J$

$= - 13.537572 k J$

$= - 13537.57$ Joule

Q. For a dimerization reaction, 2A(g)→A2​(g) at 298K,ΔU⊖,=−20kJmol−1,ΔS⊖=−30J K−1mol−1, then the ΔG⊖ will be______J.

ΔG∘=ΔH∘−TΔS∘ =(ΔU∘+Δng​RT)−TΔS∘ =[{−20+(−1))10008.314​×298}−1000298​×(−30)]kJ =−13.537572kJ =−13537.57 Joule

Q. For a dimerization reaction,
$2 A (g) \to A_{2} (g)$
at $298 K, Δ U^{⊖}, = - 20 k J m o l^{- 1}, Δ S^{⊖} = - 30 J$
$K^{- 1} m o l^{- 1}$ , then the $Δ G^{⊖}$ will be______J.

$Δ G^{\circ} = Δ H^{\circ} - T Δ S^{\circ}$

$= (Δ U^{\circ} + Δ n_{g} RT) - T Δ S^{\circ}$

$= [{- 20 + (- 1)) \frac{8.314}{1000} \times 298} - \frac{298}{1000} \times (- 30)] k J$

$= - 13.537572 k J$

$= - 13537.57$ Joule