Question

For a dilute aqueous solution, density is $1.00gc{m}^{-3}$ and $g$ (acceleration due to gravity) is $10.0m{s}^{-2}$. Then, osmotic pressure set up at highest of $0.14m$ is

• A. 0.0138 atm
• B. $1.4\times 10^{3}Pa$
• C. Both (a) and (b)
• D. None of these

Answer 1

Answer: (C)

At a column of height $h$,

Osmotic pressure $\pi =\rho gh$

$=$ density $\times g\times h$

Density, $\rho =1gc{m}^{-3}$

$\rho =\left(\frac{1}{1000}kg\right)10^6{m}^{-3}$

$\rho =10^{3}kg{m}^{-3}$

$g=10.0m{s}^{-2}$

$h=0.14m$

$\therefore \pi =10^3\times 10\times 0.14kg{m}^{-1}{s}^{-2}$

$=1.4\times 10^{3}Pa$

$\pi =\frac{1.4\times 10^{3}Pa}{1.013\times 10^{5}Paat{m}^{-1}}$

$=0.0138atm$

Thus, (a) and (b) both are correct.