For a d 4 metal ion in an octahedral field, the correct electronic configuration is :

Question

For a d 4 metal ion in an octahedral field, the correct electronic configuration is : (A) t2 g3 eg1 text when Δ0 < P (B) t2 g3 eg1 text when Δ0 > P (C) t2 g4 eg0 text when Δ0 < P (D) eg2 t2 g2 text when Δ0 < P

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/621821df6aebd3bfcfaf9d2b4bab68d2-.png" /> back pairing is not possible because pairing energy > Δo

Q. For a $d^{4}$ metal ion in an octahedral field, the correct electronic configuration is :

$t_{2 g}^{3} e_{g}^{1} when Δ_{0} < P$

$t_{2 g}^{3} e_{g}^{1} when Δ_{0} > P$

$t_{2 g}^{4} e_{g}^{0} when Δ_{0} < P$

$e_{g}^{2} t_{2 g}^{2} when Δ_{0} < P$

back pairing is not possible because pairing energy $> Δ_{o}$

Q. For a d4 metal ion in an octahedral field, the correct electronic configuration is :

t2g3​eg1​ when Δ0​<P

t2g3​eg1​ when Δ0​>P

t2g4​eg0​ when Δ0​<P

eg2​t2g2​ when Δ0​<P