For a copper block, find the electric field which can give on an average 1 eV energy to a conduction electron. (The mean free path of conduction electrons in copper is given as 4 × 10-8 m )

Question

For a copper block, find the electric field which can give on an average 1 eV energy to a conduction electron. (The mean free path of conduction electrons in copper is given as 4 × 10-8 m ) (A)  2.62 × 107 V m-1  (B)  2.64 × 107 V m-1  (C)  2.5 × 107 V m-1  (D)  2.58 × 107 V m-1

Tardigrade Admin · Accepted Answer

Energy transfer to conduction electron U=eV=e× E × d [∵ V=E × d] E=(U/e× d) =(1 eV/e×4×10-8) =(1.6×10-19J/1.6×10-19×4×10-8) =2.5×107V m-1

Q. For a copper block, find the electric field which can give on an average $1 e V$ energy to a conduction electron. (The mean free path of conduction electrons in copper is given as $4 \times 1 0^{- 8} m$ )

$2.62 \times 1 0^{7} V m^{- 1}$

$2.64 \times 1 0^{7} V m^{- 1}$

$2.5 \times 1 0^{7} V m^{- 1}$

$2.58 \times 1 0^{7} V m^{- 1}$

Energy transfer to conduction electron
$U = e V = e \times E \times d$
$[∵ V = E \times d]$
$E = \frac{U}{e \times d}$
$= \frac{1 e V}{e \times 4 \times 1 0 ^{- 8}}$
$= \frac{1.6 \times 1 0 ^{- 19} J}{1.6 \times 1 0 ^{- 19} \times 4 \times 1 0 ^{- 8}}$
$= 2.5 \times 1 0^{7} V m^{- 1}$

Q. For a copper block, find the electric field which can give on an average 1eV energy to a conduction electron. (The mean free path of conduction electrons in copper is given as 4×10−8m )

2.62×107Vm−1

2.64×107Vm−1

2.5×107Vm−1

2.58×107Vm−1