For a chemical reaction A longrightarrow Products, the rate of disappearance of A is given by: -(d C A /d t)=(K1 C A /1+K2 C A ) At very low C A , the reaction is of the ...... order with rate constant .......: (Assume K1 and K2 are lesser than 1 )

Question

For a chemical reaction A longrightarrow Products, the rate of disappearance of A is given by: -(d C A /d t)=(K1 C A /1+K2 C A ) At very low C A , the reaction is of the ...... order with rate constant .......: (Assume K1 and K2 are lesser than 1 ) (A) I , K1 / K2 (B) I , K1 (C) II , K1 / K2 (D)  II, K1 / K1+K2

Tardigrade Admin · Accepted Answer

-(d CA/d t)=(K1 CA/1+K2 CA) At very low CA: 1 gg K2 CA ;(1+K2 VA) ≈ 1 ∴ rate =-(d CA/d t)=K1 CA ; Rate constant =K1 order =1

Q. For a chemical reaction $A ⟶$ Products, the rate of disappearance of $A$ is given by:
$- \frac{d C _{A}}{d t} = \frac{K _{1} C _{A}}{1 + K _{2} C _{A}}$ At very low $C_{A}$ , the reaction is of the ...... order with rate constant ....... :
(Assume $K_{1}$ and $K_{2}$ are lesser than 1 )

$I, K_{1} / K_{2}$

$I, K_{1}$

$II, K_{1} / K_{2}$

$II, K_{1} / K_{1} + K_{2}$

$- \frac{d C _{A}}{d t} = \frac{K _{1} C _{A}}{1 + K _{2} C _{A}}$

At very low $C_{A} : 1 ≫ K_{2} C_{A}; (1 + K_{2} V_{A}) \approx 1$

$∴$ rate $= - \frac{d C _{A}}{d t} = K_{1} C_{A};$ Rate constant $= K_{1}$

order $= 1$

Q. For a chemical reaction A⟶ Products, the rate of disappearance of A is given by: −dtdCA​​=1+K2​CA​K1​CA​​ At very low CA​, the reaction is of the ...... order with rate constant ....... : (Assume K1​ and K2​ are lesser than 1 )

I,K1​/K2​

I,K1​

II,K1​/K2​

II,K1​/K1​+K2​