For a chemical reaction ; A( g )+B( l ) leftharpoons D( g )+E( g ) Hypothetically at what temperature, Kp=Kc (when, R =0.08 I - atm / mol - K )

Question

For a chemical reaction ; A( g )+B( l ) leftharpoons D( g )+E( g ) Hypothetically at what temperature, Kp=Kc (when, R =0.08 I - atm / mol - K ) (A) T=0 K (B) T=1 K (C) T=12.5 K (D) T=273 K

Tardigrade Admin · Accepted Answer

As Kp=Kc(R T) Δ ng Here Δ ng=1 So, Kp=Kc when R T=1 ⇒ 0.08 × T=1 Thus T=12.5 K

Q. For a chemical reaction ;
$A (g) + B (l) ⇌ D (g) + E (g)$
Hypothetically at what temperature, $K_{p} = K_{c}$ (when, $R = 0.08 I - a t m / m o l - K$ )

$T = 0 K$

$T = 1 K$

$T = 12.5 K$

$T = 273 K$

As $K_{p} = K_{c} (RT)^{Δ n_{g}}$
Here $Δ n_{g} = 1$
So, $K_{p} = K_{c}$ when $RT = 1 \Rightarrow 0.08 \times T = 1$
Thus $T = 12.5 K$

Q. For a chemical reaction ; A(g)+B(l)⇌D(g)+E(g) Hypothetically at what temperature, Kp​=Kc​ (when, R=0.08I−atm/mol−K )

T=0K

T=1K

T=12.5K

T=273K