Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
For a certain reaction the change in enthalpy and change in entropy are 40.63 kJ mol -1 and 100 JK -1 . What is the value of Δ G at 27° C and indicate whether the reaction is spontaneous or not-
Q. For a certain reaction the change in enthalpy and change in entropy are
40.63
k
J
m
o
l
−
1
and
100
J
K
−
1
.
What is the value of
Δ
G
at
2
7
∘
C
and indicate whether the reaction is spontaneous or not-
1622
204
Thermodynamics
Report Error
A
+
10630
J
m
o
l
−
1
; spontaneous
B
+
10630
J
m
o
l
−
1
; non spontaneous
C
−
7990
J
m
o
l
−
1
; spontaneous
D
+7900 J mol
−
1
; spontaneous
Solution:
Δ
G
=
Δ
H
−
T
Δ
S
, given
T
=
2
7
∘
C
=
273
+
27
=
300
=
40.63
×
1
0
3
−
300
×
100
=
10630
J
/
m
o
l
e
;
non-spontaneous.