For a certain reaction of order ' n ' the time for half change t1 / 2 is given by: t1 / 2=(2-√2/K) × C01 / 2 where K is rate constant and C0 is the initial concentration. The value of n is:

Question

For a certain reaction of order ' n ' the time for half change t1 / 2 is given by: t1 / 2=(2-√2/K) × C01 / 2 where K is rate constant and C0 is the initial concentration. The value of n is: (A) 1 (B) 2 (C) 0 (D) 0.5

Tardigrade Admin · Accepted Answer

This is integrated rate expression of (-d c/d t)=K C1 / 2

Q. For a certain reaction of order ' $n$ ' the time for half change $t_{1/2}$ is given by:
$t_{1/2} = \frac{2 - 2}{K} \times C_{0}^{1/2}$
where $K$ is rate constant and $C_{0}$ is the initial concentration. The value of $n$ is:

1

2

0

0.5

This is integrated rate expression of $\frac{- d c}{d t} = K C^{1/2}$

Q. For a certain reaction of order ' n ' the time for half change t1/2​ is given by: t1/2​=K2−2​​×C01/2​ where K is rate constant and C0​ is the initial concentration. The value of n is:

1

2

0

0.5

This is integrated rate expression of dt−dc​=KC1/2

Q. For a certain reaction of order ' $n$ ' the time for half change $t_{1/2}$ is given by:
$t_{1/2} = \frac{2 - 2}{K} \times C_{0}^{1/2}$
where $K$ is rate constant and $C_{0}$ is the initial concentration. The value of $n$ is:

This is integrated rate expression of $\frac{- d c}{d t} = K C^{1/2}$