Question

For a certain reaction of order ' $n$ ' the time for half change $t_{1 / 2}$ is given by:
$t_{1 / 2}=\frac{2-\sqrt{2}}{K} \times C_{0}^{1 / 2}$
where $K$ is rate constant and $C_{0}$ is the initial concentration. The value of $n$ is:

• A. 1
• B. 2
• C. 0
• D. 0.5

Answer 1

Answer: (D)

This is integrated rate expression of $\frac{-d c}{d t}=K C^{1 / 2}$