For a certain radioactive process the graph between In R and t(s e c) is obtained as shown in the figure. Then the value of half life for the unknown radioactive material is approximately :

Question

For a certain radioactive process the graph between In R and t(s e c) is obtained as shown in the figure. Then the value of half life for the unknown radioactive material is approximately : (A) 9.15 sec (B) 6.93 sec (C) 2.62 sec (D) 4.62 sec

Tardigrade Admin · Accepted Answer

R=R0 e-λ t l n R=l n R0-λ t -λ is slope of straight line λ=(3/20) t1 / 2=(l n 2/λ)=4.62

Q. For a certain radioactive process the graph between In $R$ and $t (sec)$ is obtained as shown in the figure. Then the value of half life for the unknown radioactive material is approximately :

9.15 sec

6.93 sec

2.62 sec

4.62 sec

$R = R_{0} e^{- λ t}$
$l n R = l n R_{0} - λ t$
$- λ$ is slope of straight line
$λ = \frac{3}{20}$
$t_{1/2} = \frac{l n 2}{λ} = 4.62$

Q. For a certain radioactive process the graph between In R and t(sec) is obtained as shown in the figure. Then the value of half life for the unknown radioactive material is approximately :