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Question
Chemistry
For a cell given below: Ag|Ag+||Cu2+|Cu overset-Ag+ + e- → overset+Ag E° = x Cu2+ + 2e- →, E° = y E° cell is :
Q. For a cell given below :
A
g
∣
A
g
+
∣∣
C
u
2
+
∣
C
u
A
g
+
+
e
−
−
→
A
g
+
E
∘
=
x
C
u
2
+
+
2
e
−
→
,
E
∘
=
y
E
∘
cell is :
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A
x
+
2
y
B
2
x
+
y
C
y
−
x
D
y
−
2
x
Solution:
At LHS (oxidation)
2
×
(
A
g
⟶
A
g
+
+
e
−
)
E
o
x
−
=
−
x
At RHS (reduction)
C
u
2
+
+
2
e
−
⟶
C
u
E
re
d
∘
=
+
y
__________________________________
2
A
g
+
C
u
2
+
t
o
C
u
+
2
A
g
+
,
E
re
d
∘
=
(
y
−
x
)
___________________________________
Note :
E
∘
values remain constant when half-cell equation is multipled/divided.