For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the curremt I drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r, respectively. Then

Question

For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the curremt I drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r, respectively. Then (A) E=2 V , r=0.5 Ω (B) E=2 V , r=0.4 Ω (C) E > 2 V , r=0.5 Ω (D) E > 2 V , r=0.4 Ω

Tardigrade Admin · Accepted Answer

V=E-i r. When i=0, the potential reading is 2 V. Hence emf is 2 V. When V=0, i=5 A. This gives r=0.4 Ω.

Q. For a cell, a graph is plotted between the potential difference $V$ across the terminals of the cell and the curremt $I$ drawn from the cell (see figure). The emf and the internal resistance of the cell are $E$ and $r$ , respectively. Then

$E = 2 V, r = 0.5 Ω$

$E = 2 V, r = 0.4 Ω$

$E > 2 V, r = 0.5 Ω$

$E > 2 V, r = 0.4 Ω$

$V = E - i r$ . When $i = 0$ , the potential reading is $2 V$ .
Hence emf is $2 V$ . When $V = 0, i = 5 A$ .
This gives $r = 0.4 Ω$ .

Q. For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the curremt I drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r, respectively. Then

E=2V,r=0.5Ω

E=2V,r=0.4Ω

E>2V,r=0.5Ω

E>2V,r=0.4Ω