Question

For a Bohr atom angular momentum $M$ of the electron is : $(n=0,1,2,......)$

• A. $\frac{n{h}^2}{4\pi }$
• B. $\frac{n^2{h}^2}{4\pi }$
• C. $\frac{\sqrt{n{h}^2}}{4\pi }$
• D. $\frac{nh}{2\pi }$

Answer 1

Answer: (D)

Angular momentum of electrons $=mvr=\frac{nh}{2\pi }$