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Tardigrade
Question
Chemistry
Following reaction takes place by mechanism: O 2+ CO longrightarrow NO + CO 2 Step - I: NO 2+ NO 2 xrightarrowk1, text Slow NO 3+ NO Step - II: NO 3+ CO xrightarrow k 2, textFast NO 2+ CO 2 Hence, ((d x/d t)) for the given reaction is
Q. Following reaction takes place by mechanism:
O
2
+
CO
⟶
NO
+
C
O
2
Step -
I
:
N
O
2
+
N
O
2
k
1
,
Slow
N
O
3
+
NO
Step
−
II
:
N
O
3
+
CO
k
2
,
Fast
N
O
2
+
C
O
2
Hence,
(
d
t
d
x
)
for the given reaction is
1834
298
Chemical Kinetics
Report Error
A
k
1
[
N
O
2
]
2
−
k
2
[
N
O
3
]
[
CO
]
21%
B
k
1
[
N
O
2
]
2
16%
C
k
1
[
N
O
2
]
2
+
k
2
[
N
O
3
]
[
CO
]
40%
D
k
1
[
N
O
2
]
+
k
2
[
CO
]
23%
Solution:
Slow step I is the rate-determining step.
∴
(
d
t
d
x
)
=
k
1
[
N
O
2
]
2