Question

Five equal resistors when connected in series dissipated $5W$ power. If they are connected in parallel, the power dissipated will be

• A. 25 W
• B. 50 W
• C. 100 W
• D. 125 W

Answer 1

Answer: (D)

In series, total resistance of $5$ resistors $=5R$
Power dissipated $=\frac{V^2}{5R}=5$ or $\frac{V^2}{R}=25$...(i)
In parallel, total power $=5\left[\frac{V^2}{R}\right]$
$=5\times 25=125W$ (Using(i))