Five equal resistances are connected in a network as shown in figure. The net resistance between the points A and B is:

Question

Five equal resistances are connected in a network as shown in figure. The net resistance between the points A and B is: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/df3d0c42b39b9bab56b549d510456abc-.png" /> (A) 2 R (B) ( R /2) (C) (3 R /2) (D) R

Tardigrade Admin · Accepted Answer

This diagram can be drawn like <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a7f5bc1fd4207375ad08c2f7b4fca31d-.png" /> It is a wheat stone bridge ∴ R eq =(2 R × 2 R /2 R +2 R ) ⇒ R

Q. Five equal resistances are connected in a network as shown in figure. The net resistance between the points $A$ and $B$ is :

$2 R$

$\frac{R}{2}$

$\frac{3 R}{2}$

$R$

This diagram can be drawn like

It is a wheat stone bridge
$∴ R_{e q} = \frac{2 R \times 2 R}{2 R + 2 R} \Rightarrow R$

Q. Five equal resistances are connected in a network as shown in figure. The net resistance between the points A and B is :

2R

2R​

23R​

R

This diagram can be drawn like It is a wheat stone bridge ∴Req​=2R+2R2R×2R​⇒R

Q. Five equal resistances are connected in a network as shown in figure. The net resistance between the points $A$ and $B$ is :

$2 R$

$\frac{R}{2}$

$\frac{3 R}{2}$

$R$

This diagram can be drawn like

It is a wheat stone bridge
$∴ R_{e q} = \frac{2 R \times 2 R}{2 R + 2 R} \Rightarrow R$