Question

Five equal capacitors each with capacitance $C$ are connected as shown in figure. Then, the equivalent capacitance between $A$ and $B$ is

• A. 5 C
• B. C / 5
• C. 3 C
• D. C

Answer 1

Answer: (D)

Consider the given circuit.

The circuit can be redrawn as shown below.

The circuit is a balanced bridge. We can remove the capacitor between $C$ and $D$.

Thus, equivalent capacitance between $A$ and $B$ is
$C_{AB}=\frac{C}{2}+\frac{C}{2}=C$